WebCorrect option is C) Since x,1 and z are in AP Then, 2=x+z ... (i) and x,2,z are in GP ∴4=xz ... (ii) On dividing Eq (ii) by Eq (i), we get x+zx.z= 24 ⇒ x+z2xz=4 Hence, x,4 and z will … Web21 feb. 2010 · Case 1: x=5 and y=2, with the result that x y is a multiple of 25. Case 2: x=25 and y=2, with the result that x y is a multiple of 25. Since x can be different values, …

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WebWe can assume that gcd(x,y,z) = 1; (1/x +1/y+1/z)xyz = xy +xz + yz = x(y +z)+yz, x+ y+z = 0 implies that y+ z = −x, we have x(y +z)+yz = −x2 + yz = 0. We deduce that x2 = yz, let … WebIf x > 1,y > 1,z > 1 are in GP, then 1+ln x1, 1+ln y1, 1+ln z1, are in 1288 61 IIT JEE IIT JEE 1998 Sequences and Series Report Error A AP B HP C GP D none of these Solution: Let … city of golden grants

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Web7 feb. 2024 · asked Feb 7, 2024 in Mathematics by Akul (72.6k points) If x >1, y > 1, z > 1 are in GP, then 1/ (1 + lnx), 1/ (1 + lny),1/ (1 + lnz) are in. (a) AP. (b) HP. (c) GP. (d) … WebNow get rid of the -1 on the left side by adding +1 to both sides and you have the answer of: . . You could also have begun the problem by multiplying out the left side ... multiplying y … WebThe correct option is C H.P Explanation for the correct option. As x, 1, z are in A.P, so 1 - x = z - 1 ⇒ z + x = 2 As x, 2, z are in G.P, so 2 x = z 2 ⇒ 4 = x z If x, 4, z are in H.P, then … don trey weather prediction